Assignment 5

Group Number: 107 Student #1 Name and ID: Andrew Murray 301584245 Student #2 Name and ID: Kavahn Ahluwalia 301581033

Case A

• using the data provided with the material setting it gives the yield value

$${\sigma }_y=206,807,000{\text{N/m}}^2\text{(or }206.807\text{MPa)}$$ $$\begin{array}{rl}{F}_t& ={\sigma }_y\times A\\ & =206,807,000{\text{N/m}}^2\times 7.85398\times 10^{-5}{\text{m}}^2\\ & =16,253\text{N}\text{(approximately)}\end{array}$$

• 
• As seen the simulation results are in line with the yield strength calculated earlier

Case B

• the Calculated yield strength with the given formula is $119,400,077$
• 
• Yes the yield strength on the von Mises simulation is much higher, because it could be the lever effect as the distance from the fixed point and when the force is applied to the end of the rod it and the stress concentration at the fixed point exacerbates the lever effect, though this is just a guess

Case C

• 
• Yes the piston yields because the stress is greater than the yield strength

Case D

•